Exam questions · Maths · Transformations and Similarity
Congruence and Similarity
- 6 exam questions
- 17 marks
- 9 quick checks
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1 Give a reason [2 marks]
Triangle \(ABC\) has sides of 3 cm, 4 cm and 5 cm. Triangle \(PQR\) has sides of 3 cm, 4 cm and 5 cm. Are the triangles congruent? Give a reason for your answer.
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Model answer
Yes. All three sides of one triangle are equal to the three sides of the other, so they are congruent by SSS.
Mark scheme
- Yes — B1
- All three pairs of sides are equal, or SSS — C1
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2 Prove [4 marks]
\(ABCD\) is a kite with \(AB = AD\) and \(BC = DC\). (a) Prove that triangles \(ABC\) and \(ADC\) are congruent. (3 marks) (b) Hence write down the size of angle \(ABC\) compared with angle \(ADC\). (1 mark)
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Model answer
(a) \(AB = AD\) (given), \(BC = DC\) (given) and \(AC\) is a side of both triangles. All three sides are equal, so the triangles are congruent by SSS. (b) Corresponding angles in congruent triangles are equal, so angle \(ABC\) equals angle \(ADC\).
Mark scheme
- \(AB = AD\) and \(BC = DC\) given — M1
- \(AC\) is a common side — M1
- SSS, so the triangles are congruent — C1
- (b) Angle \(ABC\) = angle \(ADC\) — B1
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3 Work out [3 marks]
Triangles \(ABC\) and \(DEF\) are similar. (a) Work out the scale factor of the enlargement from \(ABC\) to \(DEF\). (1 mark) (b) Work out the length of \(EF\). (1 mark) (c) Work out the length of \(FD\). (1 mark)
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Model answer
(a) \(DE\) matches \(AB\), so the scale factor is \(\dfrac{10}{5} = 2\). (b) \(EF = 6 \times 2 = 12\) cm. (c) \(FD = 7 \times 2 = 14\) cm.
Mark scheme
- (a) 2 — B1
- (b) 12 — B1
- (c) 14 — B1
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4 Work out [2 marks]
Triangles \(ABC\) and \(DEF\) are similar. \(AB = 4\) cm, \(BC = 6\) cm and \(DE = 10\) cm, where \(DE\) corresponds to \(AB\) and \(EF\) corresponds to \(BC\). Work out the length of \(EF\).
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Model answer
The scale factor is \(\dfrac{10}{4} = 2.5\), so \(EF = 6 \times 2.5 = 15\) cm.
Mark scheme
- \(\dfrac{10}{4}\) or 2.5 — M1
- 15 cm — A1
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5 Work out [3 marks]
Two similar shapes have lengths in the ratio \(2 : 3\). The area of the smaller shape is 20 cm\(^2\). Work out the area of the larger shape.
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Model answer
The area scale factor is \(\left(\dfrac{3}{2}\right)^2 = \dfrac{9}{4}\). The larger area is \(20 \times \dfrac{9}{4} = 45\) cm\(^2\).
Mark scheme
- \(\left(\dfrac{3}{2}\right)^2\) or \(\dfrac{9}{4}\) — M1
- \(20 \times \dfrac{9}{4}\) — M1
- 45 cm\(^2\) — A1
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6 Work out [3 marks]
Two similar solids have volumes in the ratio \(8 : 27\). The surface area of the smaller solid is 36 cm\(^2\). Work out the surface area of the larger solid.
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Model answer
The volumes are in the ratio \(8 : 27\), so the lengths are in the ratio \(\sqrt[3]{8} : \sqrt[3]{27} = 2 : 3\). The area ratio is \(4 : 9\), so the larger surface area is \(36 \times \dfrac{9}{4} = 81\) cm\(^2\).
Mark scheme
- Length ratio \(2 : 3\) — M1
- Area ratio \(4 : 9\) or the scale factor \(\dfrac{9}{4}\) — M1
- 81 cm\(^2\) — A1
Quick check
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1
Which of these is not enough to show that two triangles are congruent?
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B: Three equal angles
Three equal angles give similar triangles, which may be different sizes.
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2
Two triangles have two equal sides and the equal angle between them. Which condition is this?
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A: SAS
Side, angle, side with the angle between the sides is SAS.
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3
Two similar triangles have matching sides of 6 cm and 15 cm. What is the scale factor from the smaller to the larger?
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D: \(2.5\)
\(\dfrac{15}{6} = 2.5\).
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4
A triangle with sides 3, 4 and 5 cm is similar to a triangle with sides 9 cm, \(x\) cm and 15 cm. What is \(x\)?
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C: \(12\)
The scale factor is \(\dfrac{9}{3} = 3\), so \(x = 4 \times 3 = 12\).
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5
Triangles \(ABC\) and \(DEF\) are similar, with \(AB = 4\), \(DE = 10\) and \(BC = 6\). What is \(EF\)?
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B: 15 cm
The scale factor is \(\dfrac{10}{4} = 2.5\), so \(EF = 6 \times 2.5 = 15\) cm.
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6
Two triangles have all three angles equal. What can you say?
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A: They are similar
Equal angles make the shapes similar, but not necessarily the same size.
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7
The lengths of a shape are doubled. By what factor is the area multiplied?
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D: 4
The area scale factor is \(2^2 = 4\).
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8
The lengths of a solid are multiplied by 3. By what factor is the volume multiplied?
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C: 27
The volume scale factor is \(3^3 = 27\).
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9
Two similar shapes have areas in the ratio \(9 : 25\). What is the ratio of their lengths?
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B: \(3 : 5\)
Take square roots: \(\sqrt{9} : \sqrt{25} = 3 : 5\).