Exam questions · Maths · Circle Theorems
Same Segment and Cyclic Quadrilaterals
- 6 exam questions
- 19 marks
- 9 quick checks
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1 Calculate [2 marks]
The diagram is not drawn to scale. \(A\), \(B\), \(C\) and \(D\) are points on a circle. Angle \(ACB = 44^\circ\). Calculate angle \(ADB\), giving a reason for your answer. [2 marks]
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Model answer
Angle \(ADB = 44^\circ\), because angles in the same segment are equal.
Mark scheme
- \(44\) — B1
- Angles in the same segment are equal — B1
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2 Calculate [4 marks]
The diagram is not drawn to scale. \(ABCD\) is a cyclic quadrilateral. Angle \(ABC = 80^\circ\) and angle \(BAD = 96^\circ\). (a) Calculate angle \(ADC\), giving a reason for your answer. [2 marks] (b) Calculate angle \(BCD\). [2 marks]
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Model answer
(a) \(ADC = 180 - 80 = 100^\circ\), because opposite angles of a cyclic quadrilateral add up to \(180^\circ\). (b) \(BCD = 180 - 96 = 84^\circ\).
Mark scheme
- (a) \(100\) — B1
- (a) Opposite angles of a cyclic quadrilateral add up to 180 degrees — B1
- (b) \(180 - 96\) — M1
- (b) \(84\) — A1
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3 Calculate [3 marks]
\(ABCD\) is a cyclic quadrilateral. Angle \(A = 5x - 10\) and angle \(C = 3x + 30\). Calculate the value of \(x\). [3 marks]
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Model answer
Opposite angles add up to \(180^\circ\), so \(5x - 10 + 3x + 30 = 180\). Then \(8x = 160\) and \(x = 20\).
Mark scheme
- \((5x - 10) + (3x + 30) = 180\) — M1
- \(8x + 20 = 180\) or \(8x = 160\) — M1
- \(20\) — A1
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4 Calculate [3 marks]
The diagram is not drawn to scale. \(ABCD\) is a cyclic quadrilateral. The side \(AB\) is extended to the point \(E\). Angle \(CBE = 70^\circ\). (a) Calculate angle \(ABC\). [1 mark] (b) Calculate angle \(ADC\), giving a reason for your answer. [2 marks]
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Model answer
(a) \(ABC = 180 - 70 = 110^\circ\). (b) \(ADC = 180 - 110 = 70^\circ\), because opposite angles of a cyclic quadrilateral add up to \(180^\circ\).
Mark scheme
- (a) \(110\) — B1
- (b) \(70\) — B1
- (b) Opposite angles of a cyclic quadrilateral add up to 180 degrees — B1
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5 Calculate [4 marks]
\(A\), \(B\), \(C\) and \(D\) are points on a circle. The lines \(AC\) and \(BD\) cross at \(E\). Angle \(CAD = 48^\circ\) and angle \(ABC = 110^\circ\). (a) Calculate angle \(CBD\), giving a reason for your answer. [2 marks] (b) Calculate angle \(ADC\), giving a reason for your answer. [2 marks]
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Model answer
(a) \(CBD = 48^\circ\), because angles in the same segment are equal. (b) \(ADC = 180 - 110 = 70^\circ\), because opposite angles of a cyclic quadrilateral add up to \(180^\circ\).
Mark scheme
- (a) \(48\) — B1
- (a) Angles in the same segment are equal — B1
- (b) \(70\) — B1
- (b) Opposite angles of a cyclic quadrilateral add up to 180 degrees — B1
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6 Calculate [3 marks]
\(ABCD\) is a cyclic quadrilateral. Angle \(A = x\), angle \(B = 2x\) and angle \(C = 3x\). Calculate the size of angle \(D\). [3 marks]
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Model answer
\(A\) and \(C\) are opposite, so \(x + 3x = 180\), which gives \(x = 45\). Angle \(D\) is opposite angle \(B\), so \(D = 180 - 2 \times 45 = 90^\circ\).
Mark scheme
- \(x + 3x = 180\) — M1
- \(x = 45\) — A1
- \(D = 90\) — A1
Quick check
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1
Two angles are in the same segment of a circle. One is \(47^\circ\). What is the other?
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C: \(47^\circ\)
Angles in the same segment are equal.
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2
What do opposite angles of a cyclic quadrilateral add up to?
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B: \(180^\circ\)
This is the cyclic quadrilateral theorem.
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3
A cyclic quadrilateral has an angle of \(112^\circ\). What is the opposite angle?
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A: \(68^\circ\)
\(180 - 112 = 68\).
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4
What is a cyclic quadrilateral?
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D: A quadrilateral with all four corners on a circle
“Cyclic” means all the corners lie on one circle.
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5
In a cyclic quadrilateral \(ABCD\), \(\angle A = 2x + 10\) and \(\angle C = 3x + 20\). What is \(x\)?
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C: \(30\)
\(5x + 30 = 180\), so \(5x = 150\) and \(x = 30\).
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6
\(ABCD\) is cyclic and the side \(AB\) is extended to \(E\). Angle \(CBE = 70^\circ\). What is angle \(ADC\)?
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B: \(70^\circ\)
An exterior angle of a cyclic quadrilateral equals the interior opposite angle.
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7
Which of these must be true for the angles \(ACB\) and \(ADB\) to be equal?
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A: \(C\) and \(D\) are on the same side of the chord \(AB\)
Angles in the same segment are made on the same side of a chord.
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8
A quadrilateral has opposite angles of \(95^\circ\) and \(80^\circ\). Can it be cyclic?
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D: No, because \(95 + 80 \ne 180\)
Opposite angles of a cyclic quadrilateral must add up to \(180^\circ\), and \(95 + 80 = 175\).
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9
\(A\), \(B\), \(C\) and \(D\) are on a circle, with \(AC\) and \(BD\) meeting at \(E\). Angle \(CAD = 36^\circ\). What is angle \(CBD\)?
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C: \(36^\circ\)
Angles \(CAD\) and \(CBD\) are made by the chord \(CD\) on the same side, so they are equal.