Exam questions · Maths · Further Algebra
Inequalities and Regions
- 6 exam questions
- 18 marks
- 9 quick checks
-
1 Write down [2 marks]
\(n\) is an integer such that \(1 \leq 2n < 9\). Write down all the possible values of \(n\).
Show answerHide answer
Model answer
Dividing by 2 gives \(0.5 \leq n < 4.5\), so \(n = 1, 2, 3, 4\).
Mark scheme
- \(0.5 \leq n < 4.5\) or three correct values — M1
- 1, 2, 3, 4 — A1
-
2 Write down [5 marks]
The diagram shows a shaded region \(R\). (a) Write down the three inequalities that define \(R\). [3 marks] (b) Show that the point \((4, 5)\) is inside \(R\) or on its boundary. [2 marks]
Show answerHide answer
Model answer
(a) \(y \geq 2\), \(y \leq 2x\) and \(x + y \leq 9\). (b) \(5 \geq 2\), \(5 \leq 2 \times 4 = 8\) and \(4 + 5 = 9 \leq 9\), so the point satisfies all three inequalities, and is on the boundary \(x + y = 9\).
Mark scheme
- (a) \(y \geq 2\) — B1
- (a) \(y \leq 2x\) — B1
- (a) \(x + y \leq 9\) — B1
- (b) Substitutes \((4, 5)\) into at least two inequalities — M1
- (b) All three satisfied, with a conclusion — A1
-
3 Solve [3 marks]
Solve \(-2 < 3x + 1 \leq 10\).
Show answerHide answer
Model answer
Subtract 1: \(-3 < 3x \leq 9\). Divide by 3: \(-1 < x \leq 3\).
Mark scheme
- \(-3 < 3x \leq 9\) — M1
- \(-1 < x\) — A1
- \(x \leq 3\) — A1
-
4 Write down [2 marks]
A region is above the line \(y = 2\), below the line \(y = 5\) and to the right of the line \(x = 1\), and includes all three lines. Write down the three inequalities that define the region.
Show answerHide answer
Model answer
The inequalities are \(y \geq 2\), \(y \leq 5\) and \(x \geq 1\).
Mark scheme
- Two correct inequalities — M1
- \(y \geq 2\), \(y \leq 5\) and \(x \geq 1\) — A1
-
5 Solve [3 marks]
Solve \(x^2 - 7x + 10 < 0\).
Show answerHide answer
Model answer
\((x - 2)(x - 5) < 0\), with roots 2 and 5. The curve is below the axis between the roots, so \(2 < x < 5\).
Mark scheme
- \((x - 2)(x - 5)\) — M1
- A sketch or a clear statement that the curve is below the axis between the roots — M1
- \(2 < x < 5\) — A1
-
6 Solve [3 marks]
Solve \(x^2 - x - 12 \leq 0\).
Show answerHide answer
Model answer
\((x - 4)(x + 3) \leq 0\), with roots \(-3\) and 4. The curve is below or on the axis between the roots, so \(-3 \leq x \leq 4\).
Mark scheme
- \((x - 4)(x + 3)\) — M1
- A sketch or a clear statement that the curve is below the axis between the roots — M1
- \(-3 \leq x \leq 4\) — A1
Quick check
-
1
What does a dashed boundary line mean on a graph of an inequality?
Show answerHide answer
D: The line itself is not included
A dashed line goes with \(<\) or \(>\).
-
2
Which inequality describes the region to the right of the line \(x = 1\), including the line?
Show answerHide answer
C: \(x \geq 1\)
To the right means larger \(x\), and the line is included.
-
3
Which inequality describes the region on or below the line \(y = 2x\)?
Show answerHide answer
B: \(y \leq 2x\)
Below the line means smaller \(y\), and the line is included.
-
4
Which integers satisfy \(-2 < x \leq 3\)?
Show answerHide answer
A: \(-1, 0, 1, 2, 3\)
\(-2\) is not included but 3 is.
-
5
The origin is tested in \(x + y \leq 6\). What does this show?
Show answerHide answer
D: The origin is in the region, so shade that side
\(0 + 0 \leq 6\) is true.
-
6
How many points with whole-number coordinates satisfy \(x \geq 1\), \(y \geq 1\) and \(x + y \leq 6\)?
Show answerHide answer
C: \(15\)
The columns \(x = 1, 2, 3, 4, 5\) have \(5, 4, 3, 2, 1\) points.
-
7
Which kind of boundary line goes with the inequality \(y > 3\)?
Show answerHide answer
B: A dashed line
Strict inequalities do not include the boundary.
-
8
Solve \(x^2 - x - 6 < 0\).
Show answerHide answer
A: \(-2 < x < 3\)
The roots are \(-2\) and 3, and the curve is below the axis between them.
-
9
Solve \(x^2 > 9\).
Show answerHide answer
D: \(x < -3\) or \(x > 3\)
The curve is above the axis outside the roots \(-3\) and 3.