Exam questions · Maths · Graphs
Cubic, Reciprocal and Other Graphs
- 6 exam questions
- 17 marks
- 9 quick checks
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1 Match [3 marks]
The diagram shows three graphs, \(A\), \(B\) and \(C\). The three equations are \(y = x^2\), \(y = 2x - 1\) and \(y = x^3 - 3x\). Match each equation to the correct graph. [3 marks]
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Model answer
Graph \(A\) is an S shape with a hill and a valley, so \(y = x^3 - 3x\). Graph \(B\) is a U shape touching the origin, so \(y = x^2\). Graph \(C\) is a straight line, so \(y = 2x - 1\).
Mark scheme
- \(A\) is \(y = x^3 - 3x\) — B1
- \(B\) is \(y = x^2\) — B1
- \(C\) is \(y = 2x - 1\) — B1
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2 Complete [2 marks]
Complete the table of values for \(y = x^3 - x\). \(x = -2, -1, 0, 1, 2\)
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Model answer
The values are \(-6, 0, 0, 0, 6\).
Mark scheme
- At least three correct values — M1
- \(-6, 0, 0, 0, 6\) — A1
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3 Complete [3 marks]
(a) Complete the table of values for \(y = \dfrac{12}{x}\). \(x = 1, 2, 3, 4, 6, 12\) [2 marks] (b) For which value of \(x\) is the graph of \(y = \dfrac{12}{x}\) not defined? [1 mark]
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Model answer
(a) The values are \(12, 6, 4, 3, 2, 1\). (b) It is not defined at \(x = 0\), because you cannot divide by zero.
Mark scheme
- (a) At least four correct values — M1
- (a) \(12, 6, 4, 3, 2, 1\) — A1
- (b) \(x = 0\) — B1
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4 Calculate [3 marks]
A population of bacteria is 100 at the start. It doubles every hour, so after \(t\) hours it is \(P = 100 \times 2^t\). (a) Calculate \(P\) when \(t = 3\). [1 mark] (b) Calculate \(P\) when \(t = 5\). [1 mark] (c) Explain why the graph of \(P\) against \(t\) never touches the \(t\)-axis. [1 mark]
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Model answer
(a) \(100 \times 8 = 800\). (b) \(100 \times 32 = 3200\). (c) \(2^t\) is always greater than 0, so \(P\) is never 0.
Mark scheme
- (a) 800 — B1
- (b) 3200 — B1
- (c) \(2^t\) is never zero, so the population is never 0 — C1
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5 Calculate [3 marks]
A curve has equation \(y = x^2 - 9\). (a) Calculate the coordinates of the points where the curve crosses the \(x\)-axis. [2 marks] (b) Write down the \(y\)-intercept. [1 mark]
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Model answer
(a) When \(y = 0\), \(x^2 = 9\), so \(x = 3\) or \(x = -3\). The points are \((3, 0)\) and \((-3, 0)\). (b) The \(y\)-intercept is \(-9\).
Mark scheme
- (a) \(x^2 = 9\) — M1
- (a) \((3, 0)\) and \((-3, 0)\) — A1
- (b) \(-9\) — B1
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6 Show that [3 marks]
A circle has equation \(x^2 + y^2 = 13\). (a) Write down the radius of the circle in surd form. [1 mark] (b) Show that the point \((2, 3)\) lies on the circle. [2 marks]
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Model answer
(a) The radius is \(\sqrt{13}\). (b) \(2^2 + 3^2 = 4 + 9 = 13\), so the point lies on the circle.
Mark scheme
- (a) \(\sqrt{13}\) — B1
- (b) \(2^2 + 3^2\) or \(4 + 9\) — M1
- (b) 13 with a conclusion — A1
Quick check
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1
What shape is the graph of \(y = x^3\)?
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A: An S-shaped curve through the origin
Cubic graphs have an S shape.
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2
What is special about the graph of \(y = \dfrac{1}{x}\)?
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D: It has two branches and never touches either axis
You cannot divide by 0, and \(\dfrac{1}{x}\) is never 0.
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3
Where does the graph of \(y = 3^x\) cross the \(y\)-axis?
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C: \((0, 1)\)
\(3^0 = 1\).
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4
What is the value of \(x^3\) when \(x = -3\)?
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B: \(-27\)
\((-3) \times (-3) \times (-3) = -27\).
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5
Which of these equations gives a cubic graph?
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A: \(y = x^3 + 1\)
A cubic has \(x^3\) as its highest power.
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6
Work out \(y\) when \(x = 2\) on \(y = x^3 - 3x\).
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D: \(2\)
\(8 - 6 = 2\).
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7
What is \(2^3\)?
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C: \(8\)
\(2 \times 2 \times 2 = 8\).
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8
What shape is the graph of \(y = -x^2\)?
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B: An upside-down U
A negative \(x^2\) term turns the parabola upside down.
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9
What is the radius of the circle \(x^2 + y^2 = 36\)?
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A: \(6\)
The radius is \(\sqrt{36} = 6\).