Exam questions · Maths
Standard Form and Accuracy
- 30 exam questions
- 75 marks
- 45 quick checks
Standard Form
Just this lesson-
1 Write [2 marks]
Write 620 000 in standard form. [2 marks]
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Model answer
The decimal point moves 5 places left, so \(6.2 \times 10^5\).
Mark scheme
- 6.2 seen — M1
- \(6.2 \times 10^5\) — A1
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2 Write [2 marks]
Write \(5.6 \times 10^{-4}\) as an ordinary number. [2 marks]
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Model answer
Move the decimal point 4 places right: 0.00056.
Mark scheme
- Moves the decimal point 4 places — M1
- 0.00056 — A1
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3 Write [2 marks]
Write these numbers in order of size. Start with the largest. [2 marks] \(4 \times 10^3\) \(3.5 \times 10^4\) \(9 \times 10^2\)
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Model answer
Compare the powers: 4, 3 and 2. The order is \(3.5 \times 10^4\), \(4 \times 10^3\), \(9 \times 10^2\).
Mark scheme
- Compares the powers — M1
- \(3.5 \times 10^4\), \(4 \times 10^3\), \(9 \times 10^2\) — A1
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4 Write [3 marks]
(a) Write 38 000 000 000 in standard form. [1 mark] (b) Write 0.000000075 in standard form. [2 marks]
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Model answer
(a) \(3.8 \times 10^{10}\). (b) The point moves 8 places right, so \(7.5 \times 10^{-8}\).
Mark scheme
- (a) \(3.8 \times 10^{10}\) — B1
- (b) 7.5 seen — M1
- (b) \(7.5 \times 10^{-8}\) — A1
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5 Explain [2 marks]
Ben writes \(0.45 \times 10^6\) in standard form. Explain what is wrong, and write it correctly. [2 marks]
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Model answer
The first number, 0.45, is not at least 1 and less than 10. \(0.45 \times 10^6 = 4.5 \times 10^5\).
Mark scheme
- 0.45 is not between 1 and 10 — B1
- \(4.5 \times 10^5\) — B1
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6 Calculate [3 marks]
\(N = 9.1 \times 10^{-3}\). Write each of these in standard form. [3 marks] (a) \(10N\) [1 mark] (b) \(1000N\) [1 mark] (c) \(N \div 10\) [1 mark]
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Model answer
(a) \(9.1 \times 10^{-2}\). (b) \(9.1 \times 10^0\), which is 9.1. (c) \(9.1 \times 10^{-4}\).
Mark scheme
- (a) \(9.1 \times 10^{-2}\) — B1
- (b) \(9.1 \times 10^0\) or 9.1 — B1
- (c) \(9.1 \times 10^{-4}\) — B1
Quick check
-
1
What is 45 000 in standard form?
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B: \(4.5 \times 10^4\)
The decimal point moves 4 places left to give 4.5.
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2
What is \(3.2 \times 10^{-3}\) as an ordinary number?
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A: 0.0032
A power of \(-3\) moves the decimal point 3 places to the right of the 3, giving 0.0032.
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3
Which of these is in standard form?
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D: \(6.2 \times 10^5\)
The first part must be at least 1 and less than 10, and the base must be 10.
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4
What is 0.00045 in standard form?
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C: \(4.5 \times 10^{-4}\)
The decimal point moves 4 places right, so the power is \(-4\).
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5
What is \(45 \times 10^3\) in standard form?
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B: \(4.5 \times 10^4\)
\(45 = 4.5 \times 10\), so \(45 \times 10^3 = 4.5 \times 10^4\).
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6
Which is bigger, \(2 \times 10^7\) or \(9 \times 10^6\)?
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A: \(2 \times 10^7\)
\(2 \times 10^7 = 20\,000\,000\) and \(9 \times 10^6 = 9\,000\,000\).
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7
The distance to the Sun is about 150 million km. What is this in standard form?
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D: \(1.5 \times 10^8\) km
150 million is 150 000 000, so the point moves 8 places to give 1.5.
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8
What is \(3.2 \times 10^5\) as an ordinary number?
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C: 320 000
Move the decimal point 5 places right.
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9
Which is smaller, \(5 \times 10^{-3}\) or \(8 \times 10^{-5}\)?
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B: \(8 \times 10^{-5}\)
\(5 \times 10^{-3} = 0.005\) and \(8 \times 10^{-5} = 0.00008\).
Calculating with Standard Form
Just this lesson-
1 Calculate [2 marks]
Calculate \((2 \times 10^4) \times (4 \times 10^3)\). Give your answer in standard form. [2 marks]
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Model answer
\(2 \times 4 = 8\) and \(10^4 \times 10^3 = 10^7\), so \(8 \times 10^7\).
Mark scheme
- \(2 \times 4\) or \(10^7\) — M1
- \(8 \times 10^7\) — A1
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2 Calculate [2 marks]
Calculate \((9 \times 10^7) \div (3 \times 10^2)\). Give your answer in standard form. [2 marks]
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Model answer
\(9 \div 3 = 3\) and \(10^7 \div 10^2 = 10^5\), so \(3 \times 10^5\).
Mark scheme
- \(9 \div 3\) or \(10^5\) — M1
- \(3 \times 10^5\) — A1
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3 Calculate [3 marks]
Calculate \((5 \times 10^6) \times (4 \times 10^{-2})\). Give your answer in standard form. [3 marks]
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Model answer
\(5 \times 4 = 20\) and \(10^6 \times 10^{-2} = 10^4\), giving \(20 \times 10^4 = 2 \times 10^5\).
Mark scheme
- \(20 \times 10^4\) — M1
- Adjusts to standard form — M1
- \(2 \times 10^5\) — A1
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4 Calculate [3 marks]
Calculate \(7 \times 10^3 - 2 \times 10^2\). Give your answer in standard form. [3 marks]
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Model answer
\(7000 - 200 = 6800 = 6.8 \times 10^3\).
Mark scheme
- Same power or ordinary numbers — M1
- 6800 or \(6.8 \times 10^3\) seen — M1
- \(6.8 \times 10^3\) — A1
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5 Calculate [3 marks]
Light travels at \(3 \times 10^8\) m/s. A signal takes \(5 \times 10^2\) seconds to reach a spacecraft. Calculate the distance the signal travels. Give your answer in standard form. [3 marks]
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Model answer
Distance \(=\) speed \(\times\) time \(= (3 \times 10^8) \times (5 \times 10^2) = 15 \times 10^{10} = 1.5 \times 10^{11}\) m.
Mark scheme
- \((3 \times 10^8) \times (5 \times 10^2)\) — M1
- \(15 \times 10^{10}\) — M1
- \(1.5 \times 10^{11}\) m — A1
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6 Calculate [3 marks]
Calculate \((2.4 \times 10^{-3}) \times (5 \times 10^6)\). Give your answer in standard form. [3 marks]
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Model answer
\(2.4 \times 5 = 12\) and \(10^{-3} \times 10^6 = 10^3\), so \(12 \times 10^3 = 1.2 \times 10^4\).
Mark scheme
- \(2.4 \times 5 = 12\) — M1
- \(12 \times 10^3\) — M1
- \(1.2 \times 10^4\) — A1
Quick check
-
1
What is \((2 \times 10^3) \times (3 \times 10^4)\)?
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C: \(6 \times 10^7\)
Multiply \(2 \times 3 = 6\) and add the powers, \(3 + 4 = 7\).
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2
What is \((6 \times 10^8) \div (3 \times 10^3)\)?
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B: \(2 \times 10^5\)
Divide \(6 \div 3 = 2\) and subtract the powers, \(8 - 3 = 5\).
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3
What is \((4 \times 10^5) \times (5 \times 10^3)\) in standard form?
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A: \(2 \times 10^9\)
\(4 \times 5 = 20\) and \(10^5 \times 10^3 = 10^8\), so \(20 \times 10^8 = 2 \times 10^9\).
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4
What is \(3 \times 10^4 + 5 \times 10^3\) in standard form?
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D: \(3.5 \times 10^4\)
\(30\,000 + 5000 = 35\,000 = 3.5 \times 10^4\).
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5
What is \(6.2 \times 10^5 - 3 \times 10^4\) in standard form?
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C: \(5.9 \times 10^5\)
\(620\,000 - 30\,000 = 590\,000 = 5.9 \times 10^5\).
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6
What is \(10^7 \div 10^{-2}\)?
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B: \(10^9\)
Subtract the powers: \(7 - (-2) = 9\).
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7
What is \((4 \times 10^{-3}) \times (2 \times 10^{-2})\)?
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A: \(8 \times 10^{-5}\)
Multiply \(4 \times 2 = 8\) and add the powers, \(-3 + (-2) = -5\).
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8
What is \((3.6 \times 10^7) \div (1.2 \times 10^{-2})\)?
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D: \(3 \times 10^9\)
\(3.6 \div 1.2 = 3\) and \(10^7 \div 10^{-2} = 10^9\).
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9
\(5 \times 10^8\) bacteria, each \(2 \times 10^{-6}\) m long, are placed end to end. How long is the line?
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C: \(1 \times 10^3\) m
\(5 \times 2 = 10\) and \(10^8 \times 10^{-6} = 10^2\), so \(10 \times 10^2 = 1 \times 10^3\).
Rounding and Estimating
Just this lesson-
1 Write [2 marks]
Write 7.349 (a) correct to 1 decimal place, (b) correct to 3 significant figures. [2 marks]
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Model answer
(a) The next digit is 4, so 7.3. (b) The first three figures are 7, 3, 4, and the next digit 9 rounds the 4 up: 7.35.
Mark scheme
- (a) 7.3 — B1
- (b) 7.35 — B1
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2 Write [2 marks]
Write 0.0705 correct to 2 significant figures. [2 marks]
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Model answer
The significant figures are 7 and 0, and the next digit is 5, so round the 0 up: 0.071.
Mark scheme
- 0.07 or 0.071 seen — M1
- 0.071 — A1
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3 Estimate [3 marks]
Calculate an estimate for \(\dfrac{5.9 \times 41}{0.62}\). [3 marks]
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Model answer
\(\dfrac{6 \times 40}{0.6} = \dfrac{240}{0.6} = 400\).
Mark scheme
- Rounds to 6, 40 and 0.6 — M1
- \(\dfrac{6 \times 40}{0.6}\) — M1
- 400 — A1
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4 Estimate [3 marks]
Calculate an estimate for \(\dfrac{18.7 + 31.2}{0.51}\). [3 marks]
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Model answer
\(\dfrac{20 + 30}{0.5} = \dfrac{50}{0.5} = 100\).
Mark scheme
- Rounds to 20, 30 and 0.5 — M1
- \(\dfrac{20 + 30}{0.5}\) — M1
- 100 — A1
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5 Write [2 marks]
Write 45 678 correct to the nearest thousand. [2 marks]
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Model answer
The thousands digit is 5, and the next digit 6 rounds it up: 46 000.
Mark scheme
- 46 seen — M1
- 46 000 — A1
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6 Estimate [3 marks]
(a) Calculate an estimate for \(9.8 \times 4.9\). [2 marks] (b) Is your estimate bigger or smaller than the exact value? Give a reason. [1 mark]
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Model answer
(a) \(10 \times 5 = 50\). (b) Both numbers were rounded up, so the estimate is bigger than the exact value.
Mark scheme
- (a) 10 and 5 seen — M1
- (a) 50 — A1
- (b) Bigger, because both were rounded up — B1
Quick check
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1
What is 4.678 to 1 decimal place?
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D: 4.7
The next digit is 7, so round up.
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2
What is 6482 to 2 significant figures?
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C: 6500
The first two figures are 6 and 4, and the next digit 8 rounds the 4 up to 5, with zeros to hold the place.
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3
What is 0.004567 to 2 significant figures?
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B: 0.0046
The first significant figure is the 4, and the next digit 6 rounds the 5 up.
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4
What is 83.7 to the nearest 10?
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A: 80
83.7 is closer to 80 than to 90.
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5
What is the best estimate for \(\dfrac{4.97 \times 20.1}{0.49}\)?
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D: 200
\(\dfrac{5 \times 20}{0.5} = \dfrac{100}{0.5} = 200\).
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6
To estimate a calculation, to how many significant figures do you round each number?
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C: 1
One significant figure keeps the arithmetic easy.
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7
The bottom of a fraction is rounded up. What happens to the estimate?
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B: It is smaller than the true value
A bigger number on the bottom makes the fraction smaller.
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8
What is the best estimate for \(\dfrac{39.8 \times 5.1}{0.21}\)?
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A: 1000
\(\dfrac{40 \times 5}{0.2} = \dfrac{200}{0.2} = 1000\).
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9
What is 0.0305 to 2 significant figures?
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D: 0.031
The significant figures are 3 and 0. The next digit is 5, so round the 0 up to 1.
Error Intervals and Bounds
Just this lesson-
1 Write down [2 marks]
\(x = 250\) correct to the nearest 10. Write down the error interval for \(x\). [2 marks]
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Model answer
\(245 \leq x < 255\).
Mark scheme
- 245 and 255 seen — M1
- \(245 \leq x < 255\) — A1
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2 Write down [2 marks]
\(x = 3.45\) correct to 2 decimal places. Write down the error interval for \(x\). [2 marks]
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Model answer
Half of 0.01 is 0.005, so \(3.445 \leq x < 3.455\).
Mark scheme
- 3.445 and 3.455 seen — M1
- \(3.445 \leq x < 3.455\) — A1
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3 Write down [2 marks]
The number \(n\) is 7 after it has been truncated to a whole number. Write down the error interval for \(n\). [2 marks]
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Model answer
\(7 \leq n < 8\).
Mark scheme
- 7 and 8 seen — M1
- \(7 \leq n < 8\) — A1
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4 Calculate [3 marks]
A rectangle is 8.4 cm long and 3.2 cm wide, each correct to 1 decimal place. Calculate the upper bound of the perimeter. [3 marks]
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Model answer
The upper bounds are 8.45 cm and 3.25 cm, so the upper bound of the perimeter is \(2 \times (8.45 + 3.25) = 23.4\) cm.
Mark scheme
- 8.45 or 3.25 seen — M1
- \(2 \times (8.45 + 3.25)\) — M1
- 23.4 cm — A1
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5 Calculate [3 marks]
\(a = 9\) and \(b = 3\), each correct to the nearest integer. Calculate the lower bound of \(a - b\). [3 marks]
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Model answer
The lower bound of \(a\) is 8.5 and the upper bound of \(b\) is 3.5, so the lower bound of \(a - b\) is \(8.5 - 3.5 = 5\).
Mark scheme
- 8.5 or 3.5 seen — M1
- \(8.5 - 3.5\) — M1
- 5 — A1
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6 Calculate [3 marks]
\(a = 5\) and \(b = 4\), each correct to the nearest integer. Calculate the lower bound of \(a \times b\). [3 marks]
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Model answer
The lower bounds are 4.5 and 3.5, so the lower bound of the product is \(4.5 \times 3.5 = 15.75\).
Mark scheme
- 4.5 or 3.5 seen — M1
- \(4.5 \times 3.5\) — M1
- 15.75 — A1
Quick check
-
1
A length is 12 cm to the nearest cm. What is the error interval?
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A: \(11.5 \leq L < 12.5\)
Half a unit below and above 12, with the lower end included.
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2
\(x = 3.7\) correct to 1 decimal place. What is the error interval?
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D: \(3.65 \leq x < 3.75\)
Half of 0.1 is 0.05, so go from 3.65 up to 3.75.
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3
\(n = 5\) after being truncated to a whole number. What is the error interval?
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C: \(5 \leq n < 6\)
Truncating cuts off the digits, so the number was at least 5 and less than 6.
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4
\(x = 40\) to the nearest 10. What is the error interval?
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B: \(35 \leq x < 45\)
Half of 10 is 5.
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5
Why is the upper bound of an error interval not included?
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A: It would round up to the next value
A value exactly half way rounds up, so it belongs to the next number.
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6
\(x = 0.4\) correct to 1 significant figure. What is the error interval?
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D: \(0.35 \leq x < 0.45\)
The unit is 0.1, so half is 0.05.
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7
What is the upper bound of \(a + b\)?
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C: The upper bound of \(a\) plus the upper bound of \(b\)
The biggest total comes from the biggest values.
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8
What is the upper bound of \(a - b\)?
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B: The upper bound of \(a\) minus the lower bound of \(b\)
To make the difference big, take the biggest \(a\) and subtract the smallest \(b\).
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9
A rectangle is 8 cm by 5 cm, each to the nearest cm. What is the upper bound of its area?
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A: \(46.75\) cm\(^2\)
\(8.5 \times 5.5 = 46.75\).
Recurring Decimals and Rational Numbers
Just this lesson-
1 Write [2 marks]
(a) Write \(\dfrac{2}{5}\) as a decimal. [1 mark] (b) Write \(\dfrac{4}{9}\) as a recurring decimal, using dot notation. [1 mark]
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Model answer
(a) \(2 \div 5 = 0.4\). (b) \(0.\dot{4}\).
Mark scheme
- (a) 0.4 — B1
- (b) \(0.\dot{4}\) — B1
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2 Write [2 marks]
Write \(\dfrac{7}{12}\) as a recurring decimal, using dot notation. [2 marks]
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Model answer
\(7 \div 12 = 0.58333\ldots = 0.58\dot{3}\).
Mark scheme
- 0.5833 seen — M1
- \(0.58\dot{3}\) — A1
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3 Show that [3 marks]
Write \(0.\dot{1}\dot{5}\) as a fraction in its simplest form. [3 marks]
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Model answer
Let \(x = 0.1515\ldots\). Then \(100x = 15.1515\ldots\), so \(99x = 15\) and \(x = \dfrac{15}{99} = \dfrac{5}{33}\).
Mark scheme
- \(100x = 15.1515\ldots\) — M1
- \(99x = 15\) — M1
- \(\dfrac{5}{33}\) — A1
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4 Show that [3 marks]
Write \(0.0\dot{3}\) as a fraction in its simplest form. [3 marks]
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Model answer
Let \(x = 0.0333\ldots\). Then \(10x = 0.333\ldots\) and \(100x = 3.333\ldots\). Subtracting, \(90x = 3\), so \(x = \dfrac{3}{90} = \dfrac{1}{30}\).
Mark scheme
- \(10x\) and \(100x\) seen — M1
- \(90x = 3\) — M1
- \(\dfrac{1}{30}\) — A1
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5 Explain [2 marks]
Is \(\sqrt{49}\) rational or irrational? Give a reason. [2 marks]
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Model answer
Rational. \(\sqrt{49} = 7\), which can be written as the fraction \(\dfrac{7}{1}\).
Mark scheme
- Rational — B1
- \(\sqrt{49} = 7\) or written as a fraction — B1
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6 Show that [3 marks]
Show that \(0.\dot{3}\dot{9} = \dfrac{13}{33}\). [3 marks]
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Model answer
Let \(x = 0.3939\ldots\). Then \(100x = 39.3939\ldots\), so \(99x = 39\) and \(x = \dfrac{39}{99} = \dfrac{13}{33}\).
Mark scheme
- \(100x = 39.3939\ldots\) — M1
- \(99x = 39\) — M1
- \(\dfrac{39}{99} = \dfrac{13}{33}\) — A1
Quick check
-
1
What is \(\dfrac{3}{8}\) as a decimal?
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B: 0.375
\(3 \div 8 = 0.375\), which stops.
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2
What is \(\dfrac{1}{3}\) as a recurring decimal?
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A: \(0.\dot{3}\)
The 3 repeats for ever.
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3
What is \(\dfrac{3}{11}\) as a recurring decimal?
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D: \(0.\dot{2}\dot{7}\)
\(3 \div 11 = 0.272727\ldots\), where 27 repeats.
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4
Which fraction gives a terminating decimal?
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C: \(\dfrac{7}{20}\)
\(20 = 2^2 \times 5\), so the decimal 0.35 stops.
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5
Is \(\pi\) rational or irrational?
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B: Irrational
\(\pi\) cannot be written as a fraction.
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6
Is \(\sqrt{16}\) rational or irrational?
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A: Rational, because it equals 4
\(\sqrt{16} = 4 = \dfrac{4}{1}\).
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7
Write \(0.\dot{4}\) as a fraction.
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D: \(\dfrac{4}{9}\)
\(x = 0.\dot{4}\), \(10x = 4.\dot{4}\), so \(9x = 4\).
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8
Write \(0.\dot{4}\dot{5}\) as a fraction in its simplest form.
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C: \(\dfrac{5}{11}\)
\(100x - x = 45\), so \(x = \dfrac{45}{99} = \dfrac{5}{11}\).
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9
Write \(0.1\dot{6}\) as a fraction in its simplest form.
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B: \(\dfrac{1}{6}\)
\(100x - 10x = 15\), so \(x = \dfrac{15}{90} = \dfrac{1}{6}\).