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Independent events and tree diagrams - Exam Questions.docx

Built from the lesson script on 30 September 2026.

EDEXCEL GCSE MATHS · FOUNDATION & HIGHER

Exam Practice: Independent Events and Tree Diagrams

Independent events and tree diagrams · Probability · Lesson 4 of 6 · 17 marks · 30 minutes

Name

Date

 

Instructions

• Answer all the questions.

• Write your answers in the spaces provided.

• The marks for each question are shown in brackets - use this as a guide to how much to write.

• The answers are on separate pages at the back. Attempt every question before you look at them.

• Answer all questions. Show your working.

Question 1 NON-CALCULATOR (2 marks)

A and B are independent events. P(A) = 0.3 and P(B) = 0.5. Work out P(A and B).

(Total for Question 1 = 2 marks)

Question 2 NON-CALCULATOR (3 marks)

The probability that Amy is late for school on any day is 0.2. The tree diagram shows the probabilities for two days. Complete the tree diagram.

(Total for Question 2 = 3 marks)

Question 3 NON-CALCULATOR (2 marks)

Using the tree diagram, work out the probability that Amy is late on both days.

(Total for Question 3 = 2 marks)

Question 4 NON-CALCULATOR (3 marks)

Using the tree diagram, work out the probability that Amy is late on exactly one of the two days.

(Total for Question 4 = 3 marks)

Question 5 NON-CALCULATOR (3 marks)

Work out the probability that Amy is late on at least one of the two days.

(Total for Question 5 = 3 marks)

Question 6 NON-CALCULATOR (4 marks)

A bag contains 3 red counters and 2 blue counters. A counter is taken at random, its colour is noted and it is replaced. A second counter is taken. Work out the probability that the two counters are the same colour.

(Total for Question 6 = 4 marks)

TOTAL FOR PAPER = 17 MARKS

 

Answers and mark scheme

Check your answer only once you have written one.

Question 1 (2 marks)

0.3 × 0.5 = 0.15.

• 0.3 × 0.5 M1

• 0.15 A1

Question 2 (3 marks)

All four second-stage branches: Late 0.2 and Not late 0.8, after either first-day outcome.

• Late branches 0.2 on day 2 B1

• Not late branches 0.8 on day 2 B1

• All four correct B1

Question 3 (2 marks)

0.2 × 0.2 = 0.04.

• 0.2 × 0.2 M1

• 0.04 A1

Question 4 (3 marks)

0.2 × 0.8 + 0.8 × 0.2 = 0.16 + 0.16 = 0.32.

• One correct product M1

• Adding the two paths M1

• 0.32 A1

Question 5 (3 marks)

The probability of never being late is 0.8 × 0.8 = 0.64. So P(at least one) = 1 − 0.64 = 0.36.

• 0.8 × 0.8 M1

• 1 − 0.64 M1

• 0.36 A1

Question 6 (4 marks)

P(RR) = 3/5 × 3/5 = 9/25 and P(BB) = 2/5 × 2/5 = 4/25. Together: 13/25.

• 3/5 × 3/5 M1

• 2/5 × 2/5 M1

• Adding the two M1

• 13/25 A1