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Conditional probability - Exam Questions.docx

Built from the lesson script on 30 September 2026.

EDEXCEL GCSE MATHS · HIGHER

Exam Practice: Conditional Probability

Conditional probability · Probability · Lesson 5 of 6 · 18 marks · 30 minutes

Name

Date

 

Instructions

• Answer all the questions.

• Write your answers in the spaces provided.

• The marks for each question are shown in brackets - use this as a guide to how much to write.

• The answers are on separate pages at the back. Attempt every question before you look at them.

• Answer all questions. Show your working.

Question 1 NON-CALCULATOR (3 marks)

A bag contains 5 red counters and 3 blue counters. Two counters are taken at random without replacement. Work out the probability that both counters are red.

(Total for Question 1 = 3 marks)

Question 2 NON-CALCULATOR (3 marks)

For the same bag, work out the probability that the two counters are different colours.

(Total for Question 2 = 3 marks)

Question 3 NON-CALCULATOR (3 marks)

A bag contains 4 red counters and 6 blue counters. Two counters are taken at random without replacement. Complete the tree diagram.

(Total for Question 3 = 3 marks)

Question 4 NON-CALCULATOR (3 marks)

Using the tree diagram, work out the probability that both counters are blue.

(Total for Question 4 = 3 marks)

Question 5 NON-CALCULATOR (3 marks)

Using the tree diagram, work out the probability that at least one of the counters is red.

(Total for Question 5 = 3 marks)

Question 6 NON-CALCULATOR (3 marks)

60 students were asked whether they like football. 35 like football, and 20 of these are boys. 30 of the 60 students are boys. A student is chosen at random. Given that the student likes football, work out the probability that they are a boy.

(Total for Question 6 = 3 marks)

TOTAL FOR PAPER = 18 MARKS

 

Answers and mark scheme

Check your answer only once you have written one.

Question 1 (3 marks)

⅝ × 4/7 = 20/56 = 5/14.

• ⅝ M1

• ⅝ × 4/7 M1

• 5/14 A1

Question 2 (3 marks)

⅝ × 3/7 + ⅜ × 5/7 = 15/56 + 15/56 = 15/28.

• One correct product M1

• Adding both orders M1

• 15/28 A1

Question 3 (3 marks)

After red: red 3/9 and blue 6/9. After blue: red 4/9 and blue 5/9.

• Denominator 9 on all four branches B1

• After red: 3/9, 6/9 B1

• After blue: 4/9, 5/9 B1

Question 4 (3 marks)

6/10 × 5/9 = 30/90 = ⅓.

• 6/10 × 5/9 M1

• 30/90 A1

• ⅓ A1

Question 5 (3 marks)

1 − P(both blue) = 1 − ⅓ = ⅔.

• 1 − P(both blue) M1

• 1 − ⅓ M1

• ⅔ A1

Question 6 (3 marks)

Of the 35 who like football, 20 are boys. The probability is 20/35 = 4/7.

• 35 as the total M1

• 20/35 A1

• 4/7 A1