Skip to content

7.17 Biomass transfer and efficiency

5 exam questions worth 10 marks. Write your answer, open the mark scheme, then give yourself the marks you earned. Your answers are saved on this device.

0 / 10

1
Short answer [3 marks]

Give three reasons why not all the biomass eaten by an animal becomes new biomass in that animal.

Mark scheme

Any three from:

  • egested as faeces (not all digested / absorbed) (1)
  • excreted as urea / CO2 / water (1)
  • used in respiration (1)
  • for movement / heat (1)
  • some parts not eaten (bones) (1)

Model answer

Some is egested in faeces, some is excreted as urea and carbon dioxide, and much of the glucose is used in respiration for movement and keeping warm.

Your mark
2
Calculation [2 marks]

A field of grass contains 5000 kg of biomass. The cows that eat it gain 400 kg of biomass.

Calculate the efficiency of biomass transfer.

Mark scheme

  • 400 ÷ 5000 × 100 (1)
  • = 8% (1)

Model answer

efficiency = 400 ÷ 5000 × 100 = 8%.

Your mark
3
Short answer [2 marks]

Explain why food chains rarely have more than five trophic levels.

Mark scheme

  • biomass / energy is lost at each level (1)
  • not enough left to support further levels (1)

Model answer

So much biomass is lost at each trophic level that there is not enough left to support more levels.

Your mark
4
Short answer [2 marks]

Explain why mammals and birds have a lower efficiency of biomass transfer than fish or insects.

Mark scheme

  • mammals / birds keep their body temperature constant (1)
  • so more glucose used in respiration (for heat) (1)

Model answer

Mammals and birds use a lot of glucose in respiration to keep their bodies warm, so less is turned into new biomass.

Your mark
5
Short answer [1 mark]

About what percentage of the light energy falling on a plant is transferred into biomass?

Mark scheme

about 1%

Model answer

About 1%.

Your mark
Back to the notes

Found a mistake?