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Maths · Functions, Sequences and Rates of Change

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Rates of Change and Areas Under Graphs

Finding gradients of curves with tangents, average rates of change, and estimating areas under graphs with trapezia.

  • Higher
  • 9 key terms
  • All boards

Learning Objectives

  1. 1Find the gradient of a curve at a point by drawing and using a tangent.
  2. 2Find the average rate of change between two points, using a chord.
  3. 3Interpret gradients as rates, such as speed and acceleration, with their units.
  4. 4Estimate the area under a graph using trapezia, and say whether it is an over- or underestimate.

Rates of change

The gradient of a straight line is constant, but the gradient of a curve changes from point to point. To find the gradient at one point, you draw a tangent, a straight line that just touches the curve at that point, and find its gradient. The gradient of a graph is a rate of change. On a distance-time graph it is the speed, and on a velocity-time graph it is the acceleration. The area under a graph is also useful, and can be estimated by splitting it into trapezia. All of these skills are Higher tier on every board.

Gradient at a point

The tangent to a curve at \((4, 16)\) passes through \((2, 0)\) and \((6, 32)\). Work out the gradient of the curve at \(x = 4\), and say what it means if the graph is distance (metres) against time (seconds).

Show the solutionHide the solution
  1. 1 Rise \(32 - 0 = 32\).
  2. 2 Run \(6 - 2 = 4\).
  3. 3 Gradient \(\dfrac{32}{4} = 8\).
  4. 4 Meaning The gradient of a distance-time graph is the speed, so the speed at 4 s is 8 m/s.

AnswerThe gradient is 8, so the speed is 8 m/s

Average rate of change

The average rate of change between two points is the gradient of the chord, the straight line that joins them.

  • Chord

    A straight line joining two points on the curve.

  • Formula

    \(\dfrac{\text{change in } y}{\text{change in } x}\).

  • Example

    For \(y = x^2\) between \(x = 1\) and \(x = 4\): \(\dfrac{16 - 1}{4 - 1} = 5\).

  • Units

    The units are the \(y\) unit per \(x\) unit, such as metres per second.

The area under a graph

On a velocity-time graph the area under the curve is the distance travelled.

  • Strips

    Split the area into strips of equal width.

  • Trapezium

    Each strip is a trapezium: \(\dfrac{1}{2}(a + b)h\), where \(a\) and \(b\) are the two parallel sides and \(h\) is the width.

  • Add

    Add the areas of all the trapezia for an estimate.

  • Units

    The units of the area are the units of \(y\) times the units of \(x\), so metres per second times seconds is metres.

Over or under?

Explain whether the estimate of 80 metres is an overestimate or an underestimate of the distance travelled.

Show the solutionHide the solution
  1. 1 Look at the shape The curve bends downwards, so each straight top lies below the curve.
  2. 2 Compare areas The trapezia are inside the area under the curve.
  3. 3 Conclusion The estimate is smaller than the true value, so it is an underestimate.
  4. 4 Opposite case For a curve that bends upwards, the straight tops lie above the curve, and the estimate is an overestimate.

AnswerIt is an underestimate, because the curve is above the tops of the trapezia

Test yourself

  1. 1

    How do you find the gradient of a curve at a point?

    Show answerHide answer

    Draw a tangent and work out its gradient.

  2. 2

    What is a chord?

    Show answerHide answer

    A straight line joining two points on a curve.

  3. 3

    What is the gradient of a distance-time graph?

    Show answerHide answer

    The speed.

  4. 4

    What is the area under a velocity-time graph?

    Show answerHide answer

    The distance travelled.

  5. 5

    What is the area of a trapezium?

    Show answerHide answer

    \(\dfrac{1}{2}(a + b)h\).

Exam technique: gradients and areas

The marks are for the method, so show the numbers.

  • Tangent

    Draw it carefully with a ruler, so that it touches the curve and does not cross it.

  • Show the points

    Write down the coordinates you used to find the gradient.

  • Units

    Give units, such as m/s or m/s\(^2\).

  • Over or under

    Look at which way the curve bends, and explain with the straight edges of the trapezia.

Summary and exam focus

  • The gradient of a curve at a point is the gradient of the tangent.
  • The average rate of change is the gradient of the chord.
  • Gradient of a distance-time graph is speed, and of a velocity-time graph is acceleration.
  • Estimate the area under a curve with trapezia, and explain any over- or underestimate.

Exam focus

The tangent to a distance-time graph at \(t = 4\) passes through \((2, 0)\) and \((6, 32)\). Work out the speed at \(t = 4\). (2 marks) (2 marks)

Gradient \(= \dfrac{32 - 0}{6 - 2} = \dfrac{32}{4} = 8\), so the speed is 8 m/s. Write the units.

Key terms

The words this lesson expects you to use. Each one is linked from the first place it appears above.

Tangent
A straight line that touches a curve at one point.
Chord
A straight line joining two points on a curve.
Gradient
A measure of the steepness of a line.
Rate of change
How quickly one quantity changes compared with another.
Average rate of change
The gradient of the chord between two points.
Trapezium
A quadrilateral with one pair of parallel sides.
Estimate
An approximate answer.
Overestimate
An estimate that is larger than the true value.
Underestimate
An estimate that is smaller than the true value.

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