Exam questions · Maths · Probability
Probability Basics and Relative Frequency
- 6 exam questions
- 17 marks
- 9 quick checks
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1 Write down [2 marks]
Ten cards are numbered 1 to 10. One card is picked at random. Work out the probability that the card shows (a) a prime number, (b) a multiple of 3. [2 marks]
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Model answer
(a) The primes are 2, 3, 5 and 7, so \(\dfrac{4}{10} = \dfrac{2}{5}\). (b) The multiples of 3 are 3, 6 and 9, so \(\dfrac{3}{10}\).
Mark scheme
- (a) \(\dfrac{4}{10}\) or \(\dfrac{2}{5}\) or 0.4 — B1
- (b) \(\dfrac{3}{10}\) or 0.3 — B1
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2 Choose [3 marks]
Here are five words: impossible, unlikely, even chance, likely, certain. Choose the best word to describe each event. (a) A fair coin lands on heads. [1 mark] (b) A normal dice lands on 7. [1 mark] (c) A fair dice lands on a number less than 6. [1 mark]
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Model answer
(a) Even chance. (b) Impossible. (c) Likely, because the probability is \(\dfrac{5}{6}\).
Mark scheme
- (a) Even chance — B1
- (b) Impossible — B1
- (c) Likely — B1
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3 Work out [4 marks]
Jack spins a spinner 80 times. It lands on green 28 times. (a) Work out the relative frequency of green. Give your answer as a fraction in its simplest form. [2 marks] (b) Jack spins the spinner 200 more times. Estimate the number of times it lands on green. [2 marks]
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Model answer
(a) \(\dfrac{28}{80} = \dfrac{7}{20}\). (b) \(\dfrac{7}{20} \times 200 = 70\).
Mark scheme
- (a) \(\dfrac{28}{80}\) — M1
- (a) \(\dfrac{7}{20}\) — A1
- (b) \(\dfrac{7}{20} \times 200\) — M1
- (b) 70 — A1
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4 Work out [3 marks]
A bag contains only red, blue and yellow counters. The probability of picking a red counter is 0.3. The probability of picking a blue counter is 0.45. There are 40 counters in the bag. Work out the number of yellow counters. [3 marks]
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Model answer
\(P(\text{yellow}) = 1 - 0.3 - 0.45 = 0.25\). Then \(0.25 \times 40 = 10\) yellow counters.
Mark scheme
- \(1 - 0.3 - 0.45\) — M1
- \(0.25\) — A1
- 10 — A1
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5 Work out [2 marks]
The probability that a seed grows is 0.9. Ella plants 300 seeds. Work out an estimate for the number of seeds that grow. [2 marks]
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Model answer
\(0.9 \times 300 = 270\).
Mark scheme
- \(0.9 \times 300\) — M1
- 270 — A1
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6 Work out [3 marks]
\(A\) and \(B\) are events. \(P(A) = 0.5\), \(P(B) = 0.4\) and \(P(A \text{ or } B) = 0.7\). Work out \(P(A \text{ and } B)\). [3 marks]
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Model answer
\(P(A \text{ or } B) = P(A) + P(B) - P(A \text{ and } B)\), so \(0.7 = 0.9 - P(A \text{ and } B)\). Then \(P(A \text{ and } B) = 0.9 - 0.7 = 0.2\).
Mark scheme
- \(0.5 + 0.4 = 0.9\) — M1
- \(0.9 - 0.7\) — M1
- \(0.2\) — A1
Quick check
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1
What is the probability of an impossible event?
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B: \(0\)
An impossible event has probability 0.
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2
A bag has 3 red, 5 blue and 2 green counters. One is taken at random. What is the probability it is blue?
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A: \(\dfrac{1}{2}\)
There are 10 counters and 5 are blue, so \(\dfrac{5}{10} = \dfrac{1}{2}\).
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3
A bag has 3 red, 5 blue and 2 green counters. What is the probability that a counter taken at random is not green?
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D: \(\dfrac{4}{5}\)
\(1 - \dfrac{2}{10} = \dfrac{8}{10} = \dfrac{4}{5}\).
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4
A dice is thrown 120 times and a 6 comes up 30 times. What is the relative frequency of a 6?
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C: \(\dfrac{1}{4}\)
\(\dfrac{30}{120} = \dfrac{1}{4}\).
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5
A fair dice is thrown 600 times. How many sixes are expected?
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B: \(100\)
\(\dfrac{1}{6} \times 600 = 100\).
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6
Two fair dice are thrown. What is the probability that the total score is 7?
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A: \(\dfrac{1}{6}\)
There are 6 ways to make 7 out of 36, so \(\dfrac{6}{36} = \dfrac{1}{6}\).
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7
A bag has 3 red, 5 blue and 2 green counters. What is the probability of taking a red or a green counter?
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D: \(\dfrac{1}{2}\)
The events are mutually exclusive, so \(\dfrac{3}{10} + \dfrac{2}{10} = \dfrac{1}{2}\).
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8
A spinner is spun 200 times and lands on red 74 times. How many reds would be expected if the probability of red were \(\dfrac{1}{4}\)?
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C: \(50\)
\(\dfrac{1}{4} \times 200 = 50\). The result of 74 suggests the spinner may be biased.
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9
A card is taken from a pack of 52. What is the probability that it is a heart or a king?
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B: \(\dfrac{4}{13}\)
\(\dfrac{13}{52} + \dfrac{4}{52} - \dfrac{1}{52} = \dfrac{16}{52} = \dfrac{4}{13}\).