Exam questions · Maths · Statistics
Histograms and Sampling
- 6 exam questions
- 17 marks
- 9 quick checks
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1 Work out [3 marks]
The table shows the lengths of some worms. For the class \(0 < l \leq 2\) the frequency is 6, for \(2 < l \leq 8\) it is 18, and for \(8 < l \leq 20\) it is 24. Work out the frequency density for each class. [3 marks]
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Model answer
The widths are 2, 6 and 12. The frequency densities are \(\dfrac{6}{2} = 3\), \(\dfrac{18}{6} = 3\) and \(\dfrac{24}{12} = 2\).
Mark scheme
- Class widths 2, 6 and 12 used — M1
- At least two frequency densities correct — A1
- 3, 3 and 2 — A1
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2 Work out [4 marks]
The histogram shows the lengths, in centimetres, of some worms. (a) Work out the number of worms with a length more than 15 cm and up to 20 cm. [2 marks] (b) Work out the number of worms with a length of more than 15 cm. [2 marks]
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Model answer
(a) The frequency is the area of the bar: \(6 \times 5 = 30\). (b) The bar from 20 to 40 has a frequency of \(1.5 \times 20 = 30\), so the total is \(30 + 30 = 60\).
Mark scheme
- (a) \(6 \times 5\) — M1
- (a) 30 — A1
- (b) \(1.5 \times 20 = 30\) — M1
- (b) 60 — A1
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3 Work out [2 marks]
On a histogram the bar for the class \(5 < l \leq 15\) has a frequency density of 3. Work out an estimate for the number of values in the class \(5 < l \leq 8\). [2 marks]
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Model answer
The width of \(5 < l \leq 8\) is 3, so the estimate is \(3 \times 3 = 9\).
Mark scheme
- \(3 \times 3\) — M1
- 9 — A1
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4 Work out [3 marks]
A company has 120 staff in Sales, 80 staff in Admin and 40 staff in IT. A stratified sample of 30 staff is taken. Work out the number of staff from each department in the sample. [3 marks]
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Model answer
There are 240 staff. Sales: \(\dfrac{120}{240} \times 30 = 15\). Admin: \(\dfrac{80}{240} \times 30 = 10\). IT: \(\dfrac{40}{240} \times 30 = 5\).
Mark scheme
- \(\dfrac{120}{240} \times 30\) or the total 240 seen — M1
- At least two numbers correct — A1
- 15, 10 and 5 — A1
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5 Work out [3 marks]
In a lake, 40 fish are caught, marked and returned. Later, a sample of 90 fish is caught, and 12 of them are marked. (a) Work out an estimate for the number of fish in the lake. [2 marks] (b) State one assumption you have made. [1 mark]
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Model answer
(a) \(\dfrac{12}{90} = \dfrac{40}{N}\), so \(N = \dfrac{40 \times 90}{12} = 300\). (b) The marked fish have mixed evenly with the others, and none have joined or left the lake.
Mark scheme
- (a) \(\dfrac{40 \times 90}{12}\) — M1
- (a) 300 — A1
- (b) The marked fish have mixed evenly, or the population has not changed — B1
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6 Explain [2 marks]
Beth wants the views of residents about a new park. She asks 30 people as they leave a sports centre. (a) Give one reason why her sample may be biased. [1 mark] (b) Describe how she could improve her sampling. [1 mark]
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Model answer
(a) People at a sports centre are more likely to want a park, so they do not represent all the residents. (b) Choose people from all the residents at random, for example from the electoral roll using random numbers.
Mark scheme
- (a) The sample is not representative of all the residents — B1
- (b) A random sample from all the residents — B1
Quick check
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1
What is the formula for frequency density?
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B: Frequency divided by class width
Frequency density \(= \dfrac{\text{frequency}}{\text{class width}}\).
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2
What does the area of a bar in a histogram show?
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A: The frequency
Area \(=\) frequency density \(\times\) class width \(=\) frequency.
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3
A histogram bar has class width 20 and frequency density 3. What is the frequency?
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D: \(60\)
\(3 \times 20 = 60\).
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4
A class of width 10 has frequency 30. What is its frequency density?
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C: \(3\)
\(\dfrac{30}{10} = 3\).
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5
A survey about exercise only asks people leaving a gym. What is wrong with the sample?
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B: It is biased towards people who exercise
People at a gym are not typical of the whole population.
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6
A school has 600 pupils, 240 in Year 10. A stratified sample of 50 is taken. How many Year 10 pupils are in the sample?
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A: \(20\)
\(\dfrac{240}{600} \times 50 = 20\).
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7
50 fish are marked and released. A second sample of 40 fish contains 8 marked fish. What is the estimate of the population?
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D: \(250\)
\(\dfrac{50 \times 40}{8} = 250\).
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8
A histogram bar from 30 to 40 has frequency 40. Estimate the number of values from 30 to 35.
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C: \(20\)
35 is halfway through the class, so about half the frequency: 20.
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9
Why does a larger sample usually give a better estimate?
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B: It is more likely to represent the whole population
Bigger samples are less affected by chance.