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Maths · Angles and trigonometry

Pythagoras' theorem 1

In a right-angled triangle, the square on the longest side equals the sum of the squares on the other two. Use it to find any missing side - and to check whether a triangle is right-angled.

  • 4 key terms
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Teacher resources

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Student handouts

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Before We Start

Answer each one, then check.

  1. 1

    Work out \(13^2\).

    Show answerHide answer

    169

  2. 2

    Work out \(\sqrt{144}\).

    Show answerHide answer

    12

  3. 3

    Round 7.2111 to 1 decimal place.

    Show answerHide answer

    7.2

  4. 4

    Solve \(x^2 = 81\) (positive answer).

    Show answerHide answer

    \(x = 9\)

Learning Objectives

  1. 1Identify the hypotenuse of a right-angled triangle.
  2. 2Use Pythagoras' theorem to find the hypotenuse.
  3. 3Use Pythagoras' theorem to find a shorter side.
  4. 4Decide whether a triangle is right-angled.

The Theorem

\(a^2 + b^2 = c^2\), where \(c\) is the hypotenuse. It works ONLY in right-angled triangles.

  • Find the hypotenuse

    Square the two shorter sides, ADD, then square root.

  • Find a shorter side

    Square the hypotenuse and the known side, SUBTRACT, then square root.

  • Sense check

    The hypotenuse is always the longest side. If your "shorter side" is longer than the hypotenuse, you added when you should have subtracted.

  • Exact answers

    On the non-calculator paper, leave an answer like \(\sqrt{89}\) as a surd unless told to round.

Finding the Hypotenuse

A right-angled triangle has shorter sides 8 cm and 5 cm. Work out the length of the hypotenuse. Give your answer to 1 decimal place.

Show the solutionHide the solution
  1. 1 Write the theorem \(c^2 = 8^2 + 5^2\)
  2. 2 Square and add \(c^2 = 64 + 25 = 89\)
  3. 3 Square root \(c = \sqrt{89} = 9.433\ldots\)

Answer9.4 cm

Finding a Shorter Side

A right-angled triangle has hypotenuse 13 cm and one side 7 cm. Work out the length of the other side, to 1 decimal place.

Show the solutionHide the solution
  1. 1 Write the theorem with the hypotenuse on its own \(a^2 + 7^2 = 13^2\)
  2. 2 Subtract \(a^2 = 169 - 49 = 120\)
  3. 3 Square root \(a = \sqrt{120} = 10.954\ldots\)
  4. 4 Check: shorter than 13 Yes

Answer11.0 cm

Is It Right-Angled?

The theorem also works backwards.

  • The test

    Square the three sides. If the two smaller squares add up to the largest square, the triangle is right-angled.

  • Example

    5, 12, 13: \(25 + 144 = 169 = 13^2\), so it is right-angled.

  • Counter-example

    9, 12, 16: \(81 + 144 = 225\), but \(16^2 = 256\), so it is NOT right-angled.

  • Pythagorean triples

    Whole-number sides that fit: 3, 4, 5; 5, 12, 13; 8, 15, 17; 7, 24, 25 - and any multiple, such as 6, 8, 10.

Case study

Plimpton 322

Pythagoras lived around 500 BC, but the idea is much older. A Babylonian clay tablet called Plimpton 322, written about 1800 BC and now in a library in New York, lists fifteen rows of numbers written in base 60. Read correctly, each row gives the sides of a right-angled triangle with whole-number (or simple) sides - including triples as large as 12 709, 13 500 and 18 541. Nobody knows exactly how the Babylonians found them, but they clearly understood the rule more than a thousand years before the Greeks proved it.

About 1800 BC When Plimpton 322 was written
15 rows Of Pythagorean triples, in base 60

Triple Hunt

(a) Show that 8, 15, 17 is a Pythagorean triple. (b) Multiply 3, 4, 5 by 2, 3 and 10 and check that each result is a triple. (c) Find the missing number in the triple 20, 21, ?. (d) Explain why no triple can have all three numbers odd.

1. Square each number.

2. Add the two smaller squares.

3. Compare with the largest.

A good answer shows: (a) \(64 + 225 = 289 = 17^2\). (b) 6, 8, 10; 9, 12, 15; 30, 40, 50 all work. (c) \(400 + 441 = 841\), so 29. (d) Odd squared is odd, and odd + odd = even, so the third square would be even - and then the third number would be even.

Can I...?

  1. 1Identify the hypotenuse.
  2. 2Find the hypotenuse.
  3. 3Find a shorter side.
  4. 4Give an answer to a sensible accuracy.
  5. 5Leave an answer as a surd.
  6. 6Decide whether a triangle is right-angled.

Summary & Exam Focus

  • \(a^2 + b^2 = c^2\), with \(c\) the hypotenuse, opposite the right angle.
  • Longest side: square, add, square root.
  • Shorter side: square, subtract, square root.
  • Converse: if \(a^2 + b^2 = c^2\), the triangle is right-angled.

Exam focus

A ladder 5 m long leans against a vertical wall. The foot of the ladder is 1.8 m from the wall on horizontal ground. How far up the wall does the ladder reach? Give your answer to 2 decimal places. (3 marks) (3 marks)

Draw and label a sketch, and mark the hypotenuse first. Then decide: finding the hypotenuse means add, finding a shorter side means subtract.

Key terms

The vocabulary this lesson expects you to use. Each one is linked from the first place it appears above.

Hypotenuse
The longest side of a right-angled triangle, opposite the right angle.
Pythagoras' theorem
In a right-angled triangle, \(a^2 + b^2 = c^2\), where \(c\) is the hypotenuse.
Pythagorean triple
Three whole numbers that fit the theorem, such as 3, 4, 5.
Surd
A square root that cannot be written exactly as a fraction, such as \(\sqrt{2}\).

Questions and answers

7 questions set on this lesson, with the mark schemes and model answers open.

1. Exam question Non-calculator 2 marks Easier

A right-angled triangle has shorter sides of 7 cm and 24 cm. Work out the length of the hypotenuse.

Mark scheme — 2 marks available

  • \(7^2 + 24^2\) — M1
  • 25 cm — A1

Model answer

\(7^2 + 24^2 = 49 + 576 = 625\), \(\sqrt{625} = 25\) cm

2. Exam question Calculator 3 marks Easier

A ladder 5 m long leans against a vertical wall. The foot of the ladder is on horizontal ground, 1.8 m from the wall. How far up the wall does the ladder reach? Give your answer to 2 decimal places.

A 5 metre ladder leaning against a vertical wall with its foot 1.8 metres from the wall, and the height up the wall marked h.

Mark scheme — 3 marks available

  • \(5^2 - 1.8^2\) — M1
  • \(\sqrt{21.76}\) — M1
  • 4.66 — A1

Model answer

\(h^2 = 5^2 - 1.8^2 = 25 - 3.24 = 21.76\), so \(h = \sqrt{21.76} = 4.6647\ldots = 4.66\) m

3. Exam question Non-calculator 2 marks Easier

A triangle has sides of 9 cm, 12 cm and 16 cm. Is it a right-angled triangle? Show how you decide.

Mark scheme — 2 marks available

  • \(9^2 + 12^2 = 225\) and \(16^2 = 256\) — M1
  • Not right-angled, with the comparison — C1

Model answer

\(9^2 + 12^2 = 81 + 144 = 225\). \(16^2 = 256\). \(225 \ne 256\), so it is not right-angled.

4. Exam question Non-calculator 3 marks Easier

A rectangular field is 20 m long and 15 m wide. Jo walks diagonally across it, from one corner to the opposite corner. Tom walks along two sides. How much further does Tom walk than Jo?

Mark scheme — 3 marks available

  • \(20^2 + 15^2\) — P1
  • 25 m — P1
  • 10 m — A1

Model answer

Jo: \(\sqrt{20^2 + 15^2} = \sqrt{400 + 225} = \sqrt{625} = 25\) m. Tom: \(20 + 15 = 35\) m. Tom walks \(35 - 25 = 10\) m further.

5. Multiple choice 1 mark Easier

Which side of a right-angled triangle is the hypotenuse?

  1. A The side opposite the right angle Correct
  2. B The shortest side
  3. C The side next to the right angle
  4. D The vertical side

Why: The hypotenuse is opposite the right angle, and it is always the longest side.

6. Multiple choice 1 mark Core

A right-angled triangle has hypotenuse 10 cm and one side 6 cm. How long is the third side?

  1. A 4 cm
  2. B 11.7 cm
  3. C 8 cm Correct
  4. D 16 cm

Why: \(10^2 - 6^2 = 100 - 36 = 64\), and \(\sqrt{64} = 8\).

7. Multiple choice 1 mark Stretch

Which of these is a Pythagorean triple?

  1. A 4, 5, 6
  2. B 6, 8, 12
  3. C 10, 24, 25
  4. D 9, 40, 41 Correct

Why: \(9^2 + 40^2 = 81 + 1600 = 1681 = 41^2\).