OpenRevise GCSE

Viewing as

Student Teacher

Teaching this? The teacher view adds 2 files, the mark schemes and the model answers.

Maths · Graphs

Cubic and reciprocal graphs

Plotting cubic graphs such as \(y = x^3 - 4x\) and reciprocal graphs such as \(y = \dfrac{12}{x}\), and recognising linear, quadratic, cubic and reciprocal graphs by their shape.

  • 4 key terms
  • All boards
Download the full pack · 3 files

Last Lesson and Before

Answer each one, then check.

  1. 1

    Work out \((-2)^3\).

    Show answerHide answer

    \(-8\)

  2. 2

    Last lesson: what shape is the graph of \(y = x^2\)?

    Show answerHide answer

    A U-shaped parabola

  3. 3

    Work out \(12 \div 0.5\).

    Show answerHide answer

    24

  4. 4

    What is the reciprocal of 3?

    Show answerHide answer

    \(\frac{1}{3}\)

Learning Objectives

  1. 1Complete a table of values for a cubic and plot its graph.
  2. 2Complete a table of values for a reciprocal and plot its graph.
  3. 3Recognise and sketch linear, quadratic, cubic and reciprocal graphs.
  4. 4Use a graph to solve equations.

Cubic Graphs

A cubic has an \(x^3\) term and no higher power.

  • \(y = x^3\)

    Passes through the origin: \((-2, -8)\), \((-1, -1)\), \((0, 0)\), \((1, 1)\), \((2, 8)\).

  • S-shape

    Positive \(x^3\): rises from bottom left to top right. Negative \(x^3\): falls from top left to bottom right.

  • Up to three roots

    \(y = x^3 - 4x = x(x - 2)(x + 2)\) crosses the \(x\)-axis at \(-2\), 0 and 2.

  • Cube negatives carefully

    \((-3)^3 = -27\), so \(x^3 - 4x\) at \(x = -3\) is \(-27 + 12 = -15\).

A Table of Values for y = x³ − 4x

  • \(-3\)

    \(x^3\): \(-27\). \(-4x\): 12. y: \(-15\)

  • \(-2\)

    \(x^3\): \(-8\). \(-4x\): 8. y: 0

  • \(-1\)

    \(x^3\): \(-1\). \(-4x\): 4. y: 3

  • 0

    \(x^3\): 0. \(-4x\): 0. y: 0

  • 1

    \(x^3\): 1. \(-4x\): \(-4\). y: \(-3\)

  • 2

    \(x^3\): 8. \(-4x\): \(-8\). y: 0

  • 3

    \(x^3\): 27. \(-4x\): \(-12\). y: 15

Reciprocal Graphs

A reciprocal graph has the form \(y = \dfrac{k}{x}\).

  • No value at \(x = 0\)

    You cannot divide by 0, so there is no point on the \(y\)-axis.

  • Two separate branches

    For positive \(k\), one branch is in the top right and one in the bottom left.

  • Asymptotes

    The curve gets closer and closer to both axes but never touches them.

  • Negative \(k\)

    The branches are in the top left and bottom right instead.

Plotting y = 12/x

Complete a table of values for \(y = \dfrac{12}{x}\) for \(x = 1, 2, 3, 4, 6, 12\), and describe the graph.

Show the solutionHide the solution
  1. 1 Divide 12 by each value \(12, 6, 4, 3, 2, 1\)
  2. 2 Plot and join with a smooth curve It falls steeply, then levels off
  3. 3 Negative values \(x = -1\) gives \(-12\), \(x = -2\) gives \(-6\): the same shape, upside down, in the bottom left

Answer\(y = 12, 6, 4, 3, 2, 1\). The curve never touches either axis.

Match the Equation to the Graph

  • \(y = 3 - 2x\)

    Straight line sloping down

  • \(y = x^2 - 1\)

    U-shaped parabola

  • \(y = -x^2 + 4\)

    ∩-shaped parabola

  • \(y = x^3 + 1\)

    S-shaped curve rising to the right

  • \(y = \dfrac{5}{x}\)

    Two branches, top right and bottom left

  • \(y = -\dfrac{5}{x}\)

    Two branches, top left and bottom right

Graph Sketch Race

Your teacher calls out an equation. Sketch its graph on a mini-whiteboard in 20 seconds: \(y = 4\), \(y = x^3\), \(y = -x^2\), \(y = \frac{2}{x}\), \(y = 2x - 3\), \(y = -x^3\), \(x = -1\), \(y = x^2 + 2\), \(y = -\frac{3}{x}\).

1. Decide the type from the highest power.

2. Decide the direction from the sign.

3. Mark any intercepts.

A good answer shows: Horizontal line; S-shape rising; ∩-shape through the origin; branches top-right and bottom-left; straight line through \((0, -3)\), gradient 2; S-shape falling; vertical line; U-shape with minimum \((0, 2)\); branches top-left and bottom-right.

Can I...?

  1. 1Complete a table of values for a cubic.
  2. 2Plot a cubic graph.
  3. 3Complete a table of values for a reciprocal graph.
  4. 4Plot a reciprocal graph.
  5. 5Recognise linear, quadratic, cubic and reciprocal graphs.
  6. 6Explain why \(y = \frac{k}{x}\) has no point at \(x = 0\).

Summary & Exam Focus

  • Cubic: S-shaped, up to three roots.
  • Reciprocal \(y = \frac{k}{x}\): two branches, never touching the axes.
  • The highest power of \(x\) tells you the type of graph.

Exam focus

Match each equation to one of the graphs A, B, C and D: \(y = 3 - 2x\), \(y = x^2 - 1\), \(y = x^3\), \(y = \dfrac{5}{x}\). (2 marks) (2 marks)

In a matching question, start with the equations you are surest of - the straight line and the reciprocal are usually easiest - and eliminate.

Key terms

The vocabulary this lesson expects you to use. Each one is linked from the first place it appears above.

Cubic
An expression whose highest power of \(x\) is \(x^3\).
Reciprocal graph
A graph of the form \(y = \frac{k}{x}\).
Asymptote
A line that a curve gets closer and closer to but never touches.
Root
An \(x\)-value where a graph crosses the \(x\)-axis.

Practice questions

Have a go at each one before you open its answer.

  1. Question 1 Non-calculator 2 marks

    Complete the table of values for \(y = x^3 - 4x\) for \(x = -3, -2, -1, 0, 1, 2, 3\).

    Show answerHide answer

    Model answer

    \(y = -15, 0, 3, 0, -3, 0, 15\)

    Mark scheme

    • At least 4 correct values — B1
    • All 7 correct — B1
  2. Question 2 Non-calculator 2 marks

    Here are four graphs, A, B, C and D. Match each equation to its graph: \(y = 3 - 2x\), \(y = x^2 - 1\), \(y = x^3\), \(y = \dfrac{5}{x}\).

    Four sketch graphs labelled A to D: a U-shaped parabola, a two-branched reciprocal curve, a line sloping down and an S-shaped cubic.
    Show answerHide answer

    Model answer

    \(y = 3 - 2x\) - C. \(y = x^2 - 1\) - A. \(y = x^3\) - D. \(y = \frac{5}{x}\) - B.

    Mark scheme

    • 2 correct matches — B1
    • All 4 correct — B1
  3. Question 3 Non-calculator 3 marks

    (a) Complete the table of values for \(y = \dfrac{12}{x}\) for \(x = 1, 2, 3, 4, 6, 12\). (b) Explain why the graph of \(y = \dfrac{12}{x}\) never crosses the \(y\)-axis.

    Show answerHide answer

    Model answer

    (a) \(12, 6, 4, 3, 2, 1\) (b) On the \(y\)-axis \(x = 0\), and you cannot divide 12 by 0, so there is no point with \(x = 0\).

    Mark scheme

    • (a) At least 4 correct — B1
    • (a) All correct — B1
    • (b) Division by 0 is impossible, or \(x\) cannot be 0 — C1
  4. Question 4 Non-calculator 2 marks

    Write down the three values of \(x\) where the graph of \(y = x^3 - 4x\) crosses the \(x\)-axis. Show how you know.

    Show answerHide answer

    Model answer

    \(x^3 - 4x = x(x^2 - 4) = x(x - 2)(x + 2)\). So \(x = 0\), 2 or \(-2\). (Or: the table gives \(y = 0\) at these values.)

    Mark scheme

    • A correct method, e.g. factorising or a table — M1
    • \(-2\), 0 and 2 — A1

Quick check

  1. What shape is the graph of \(y = x^3\)?

    1. AA straight line
    2. BA U-shape
    3. CTwo separate branches
    4. DAn S-shape
    Show answerHide answer

    D: An S-shape

    A positive cubic is S-shaped, rising from bottom left to top right.

  2. What is \(y\) when \(x = -2\) on \(y = x^3 + 5\)?

    1. A\(-3\)
    2. B13
    3. C\(-1\)
    4. D3
    Show answerHide answer

    A: \(-3\)

    \((-2)^3 + 5 = -8 + 5 = -3\).

  3. Which graph has asymptotes along both axes?

    1. A\(y = x^2\)
    2. B\(y = \dfrac{4}{x}\)
    3. C\(y = x^3\)
    4. D\(y = 4x\)
    Show answerHide answer

    B: \(y = \dfrac{4}{x}\)

    A reciprocal graph gets closer to both axes but never touches them.

Downloads

Free to keep, print and annotate.

Download all 3 as a zip
Something here looks wrong?

Tell us what and we will go and look. It goes to whoever writes these pages, nobody else, and we do not ask who you are — so there is nothing to sign and nothing comes back to you.