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3.8 Concentration of solutions in g/dm³

5 exam questions worth 9 marks. Write your answer, open the mark scheme, then give yourself the marks you earned. Your answers are saved on this device.

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1
Multiple choice [1 mark]

How many cm3 are there in 1 dm3?

Choose one answer.

Correct Not quite: the answer is 1000

Mark scheme

C

Model answer

C: 1 dm3 = 1000 cm3.

2
Calculation [2 marks]

8.0 g of sodium hydroxide is dissolved in water to make 200 cm3 of solution.

Calculate the concentration in g/dm3.

Mark scheme

  • volume = 200 ÷ 1000 = 0.20 dm3 (1)
  • 8.0 ÷ 0.20 = 40 g/dm3 (1)

Model answer

Volume = 0.20 dm3, so concentration = 8.0 ÷ 0.20 = 40 g/dm3.

Your mark
3
Calculation [2 marks]

Calculate the mass of copper sulfate in 25 cm3 of a solution with a concentration of 80 g/dm3.

Mark scheme

  • 25 cm3 = 0.025 dm3 (1)
  • 80 × 0.025 = 2.0 g (1)

Model answer

mass = 80 × 0.025 = 2.0 g

Your mark
4
Short answer [2 marks]

A student dissolves 10 g of salt in 500 cm3 of solution, then adds water to make the volume 1000 cm3.

Describe and explain how the concentration changes.

Mark scheme

  • the concentration halves / falls from 20 to 10 g/dm3 (1)
  • the same mass of solute is in double the volume (1)

Model answer

The concentration halves, from 20 g/dm3 to 10 g/dm3, because the same mass of salt is now spread through twice the volume.

Your mark
5
Calculation [2 marks]

What volume of solution, in cm3, contains 3.0 g of solute if the concentration is 60 g/dm3?

Mark scheme

  • volume = 3.0 ÷ 60 = 0.050 dm3 (1)
  • = 50 cm3 (1)

Model answer

volume = mass ÷ concentration = 0.050 dm3 = 50 cm3.

Your mark
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