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Maths · Algebra
Linear sequences
A linear sequence goes up or down by the same amount every time. Its nth term is a formula that gives any term straight away - the 100th as easily as the 1st - and tells you whether a number is in the sequence at all.
Teacher resources
The teacher copies: slides with the questions built in, the answers, and anything else attached to this lesson for whoever is teaching it.
- Linear sequences - Teacher Slides.pptx Teacher The lesson slides with the teacher's notes on each slide, and every question and mark scheme built in. Built from the lesson script on 28 September 2026. View
- Linear sequences - Teacher Notes.docx Teacher The complete notes with the teacher's notes and every model answer in full. Built from the lesson script on 28 September 2026. View
Student handouts
The same files the students see, to print or hand out.
- Linear sequences.pptx Built from the lesson script on 28 September 2026. View
- Linear sequences - Completed Notes.docx The full notes for the lesson, to revise from. Built from the lesson script on 28 September 2026. View
- Linear sequences - Exam Questions.docx Built from the lesson script on 28 September 2026. View
Last Lesson and Before
Answer each one, then check.
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1
Write down the next term: 3, 7, 11, 15, ...
Show answerHide answer
19
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2
What is the difference between the terms of 20, 17, 14, ...?
Show answerHide answer
\(-3\)
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3
Solve \(3n + 2 = 50\).
Show answerHide answer
\(n = 16\)
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4
Last lesson: work out \(2n + 1\) when \(n = 10\).
Show answerHide answer
\(21\)
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5
Last lesson: make \(n\) the subject of \(T = 4n - 1\).
Show answerHide answer
\(n = \dfrac{T + 1}{4}\)
Learning Objectives
- 1Continue a sequence using a term-to-term rule.
- 2Generate terms of a sequence from its nth term.
- 3Find the nth term of a linear (arithmetic) sequence.
- 4Decide whether a number is a term of a sequence.
- 5Solve problems with linear sequences and patterns.
Sequences
A sequence is a list of numbers that follows a rule.
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Term
Each number in a sequence. The 1st term, 2nd term and so on.
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Term-to-term rule
How to get from one term to the next: "add 3".
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Position-to-term rule (nth term)
A formula for any term from its position \(n\): the nth term \(3n + 2\) gives 5, 8, 11, ...
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Linear (arithmetic) sequence
One that goes up or down by the same amount - the common difference - every time.
Where the nth Term Comes From
The sequence 5, 8, 11, 14, ... goes up by 3, so compare it with the 3 times table.
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1
3n: 3. Term: 5. Term − 3n: \(+2\)
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2
3n: 6. Term: 8. Term − 3n: \(+2\)
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3
3n: 9. Term: 11. Term − 3n: \(+2\)
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4
3n: 12. Term: 14. Term − 3n: \(+2\)
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\(n\)
3n: \(3n\). Term: \(3n + 2\). Term − 3n: \(+2\)
Finding the nth Term
Works for every linear sequence.
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1
Difference
Find the common difference, \(d\).
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2
Times table
Write down \(dn\): the \(d\) times table.
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3
Compare
How do you get from \(dn\) to the sequence?
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4
Adjust
Add or subtract that number.
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5
Check
Put \(n = 1\) and \(n = 2\) into your answer.
Finding the nth Term
Find the nth term of 7, 11, 15, 19, ...
Show the solutionHide the solution
- 1 The common difference is \(+4\) so it starts \(4n\)
- 2 The 4 times table 4, 8, 12, 16
- 3 Compare with the sequence \(7 - 4 = 3\): each term is 3 more
- 4 Write the nth term \(4n + 3\)
- 5 Check \(n = 3\) \(4 \times 3 + 3 = 15\)
Answer\(4n + 3\)
A Decreasing Sequence
Find the nth term of 20, 17, 14, 11, ...
Show the solutionHide the solution
- 1 The common difference is \(-3\) so it starts \(-3n\)
- 2 The \(-3\) times table \(-3\), \(-6\), \(-9\), \(-12\)
- 3 Compare with the sequence \(20 - (-3) = 23\): each term is 23 more
- 4 Write the nth term \(-3n + 23\), usually written \(23 - 3n\)
- 5 Check \(n = 1\) \(23 - 3 = 20\)
Answer\(23 - 3n\)
Is It in the Sequence?
Is 100 a term of the sequence with nth term \(4n + 3\)?
Show the solutionHide the solution
- 1 Set the nth term equal to 100 \(4n + 3 = 100\)
- 2 Solve \(4n = 97\), so \(n = 24.25\)
- 3 \(n\) must be a whole number (a position) 24.25 is not a whole number
AnswerNo - 100 is not in the sequence (the 24th term is 99 and the 25th is 103).
A Matchstick Pattern
Each new square needs 3 more matchsticks, so the sequence 4, 7, 10, ... has a common difference of 3. Comparing with \(3n\) (3, 6, 9) shows each pattern uses one more: the nth pattern needs \(3n + 1\) matchsticks - the extra 1 is the first stick on the left.
4, 7, 10, ...: each new square needs 3 more matchsticks.
Using the Pattern
Pattern \(n\) uses \(3n + 1\) matchsticks. (a) How many matchsticks does pattern 20 use? (b) What is the largest pattern that can be made with 100 matchsticks?
Show the solutionHide the solution
- 1 (a) Substitute \(n = 20\) \(3 \times 20 + 1 = 61\)
- 2 (b) The number of matchsticks must be 100 or fewer \(3n + 1 \le 100\)
- 3 Solve \(3n \le 99\), so \(n \le 33\)
- 4 Pattern 33 uses exactly \(3 \times 33 + 1 = 100\) it fits
Answer(a) 61 matchsticks (b) Pattern 33
Sequence Detectives
For each sequence, find the nth term and the 50th term. Then decide whether 150 is in it. (a) 6, 11, 16, 21, ... (b) 1, 4, 7, 10, ... (c) 40, 36, 32, 28, ... (d) \(-5\), \(-3\), \(-1\), 1, ...
1. Find the difference.
2. Write the nth term and check it.
3. Solve nth term = 150.
A good answer shows: (a) \(5n + 1\); 251; 150 is not in it (\(n = 29.8\)). (b) \(3n - 2\); 148; 150 is not in it (\(n = 50.67\)). (c) \(44 - 4n\); \(-156\); 150 is not in it (it is decreasing from 40). (d) \(2n - 7\); 93; 150 is not in it (\(n = 78.5\)).
Can I...?
- 1Continue a sequence.
- 2Describe a term-to-term rule.
- 3Work out terms from an nth term.
- 4Find the nth term of an increasing sequence.
- 5Find the nth term of a decreasing sequence.
- 6Decide whether a number is in a sequence.
- 7Find the nth term of a pattern.
- 8Use an nth term to solve a problem.
Summary & Exam Focus
- A linear sequence has a common difference.
- nth term = (difference) \(\times\ n\), then adjust with a number.
- To test a number, set the nth term equal to it: a whole-number \(n\) means it is in the sequence.
- For patterns, the difference is how many more items each new pattern needs.
Exam focus
Here are the first five terms of a sequence: 5, 9, 13, 17, 21. Find an expression for the nth term. (2 marks) (2 marks)
"\(n + 4\)" is the term-to-term rule written wrongly, not an nth term. The nth term of a sequence going up by 4 always starts \(4n\).
Key terms
The vocabulary this lesson expects you to use. Each one is linked from the first place it appears above.
- Sequence
- A list of numbers or patterns that follows a rule.
- Term
- One number in a sequence.
- Term-to-term rule
- The rule that gets you from one term to the next.
- nth term
- A formula that gives any term from its position, \(n\).
- Common difference
- The amount a linear sequence goes up or down by each time.
- Linear (arithmetic) sequence
- A sequence with a common difference.
Questions and answers
8 questions set on this lesson, with the mark schemes and model answers open.
Here are the first five terms of a sequence: 5, 9, 13, 17, 21. Find an expression, in terms of \(n\), for the nth term of the sequence.
Mark scheme — 2 marks available
- \(4n + 1\) — B2
- \(4n + k\), where \(k \ne 1\) — B1
Model answer
\(4n + 1\)
Is 99 a term of the sequence 5, 9, 13, 17, 21, ...? You must give a reason for your answer.
Mark scheme — 2 marks available
- \(4n + 1 = 99\), or listing terms to 97 and 101 — M1
- No, with a correct reason — C1
Model answer
\(4n + 1 = 99\) gives \(n = 24.5\), which is not a whole number, so 99 is not a term. (The terms go 97, 101.)
Find an expression for the nth term of the sequence 30, 26, 22, 18, ...
Mark scheme — 2 marks available
- \(34 - 4n\) — B2
- \(-4n + k\), where \(k \ne 34\) — B1
Model answer
\(34 - 4n\)
The diagram shows the first three patterns in a sequence made from matchsticks. Pattern 1 uses 4 matchsticks, pattern 2 uses 7 and pattern 3 uses 10. Jack has 150 matchsticks. What is the largest pattern number he can make?
Mark scheme — 3 marks available
- \(3n + 1\), or the difference of 3 used — P1
- \(3n + 1 = 150\) or \(3n + 1 \le 150\), or \(49.6\ldots\) seen — P1
- 49 — A1
Model answer
The nth pattern uses \(3n + 1\) matchsticks. \(3n + 1 \le 150\), so \(3n \le 149\) and \(n \le 49.67\). The largest pattern is pattern 49 (it uses 148 matchsticks).
Sequence A has nth term \(3n + 5\). Sequence B has nth term \(50 - 2n\). For which value of \(n\) are the nth terms of the two sequences equal, and what is that term?
Mark scheme — 3 marks available
- \(3n + 5 = 50 - 2n\) — M1
- \(n = 9\) — A1
- 32 — A1
Model answer
\(3n + 5 = 50 - 2n\), so \(5n = 45\) and \(n = 9\). The term is \(3 \times 9 + 5 = 32\).
What is the 10th term of the sequence with nth term \(3n - 1\)?
Why: \(3 \times 10 - 1 = 29\).
What is the nth term of 2, 7, 12, 17, ...?
Why: The difference is 5, so \(5n\): 5, 10, 15. Each term is 3 less: \(5n - 3\).
What is the nth term of 15, 13, 11, 9, ...?
Why: The difference is \(-2\), so \(-2n\): \(-2\), \(-4\), \(-6\). Each term is 17 more: \(17 - 2n\).